What are the solutions to the equation (6x-4)(3x+5)=(4x-9)(3x+5) ?

The solutions to the equation (6x-4)(3x+5)=(4x-9)(3x+5) are x=-5/3 ,x=-5/2

Find the zeros of (6x-4)(3x+5)=(4x-9)(3x+5)

The zeros of (6x-4)(3x+5)=(4x-9)(3x+5) are x=-5/3 ,x=-5/2

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(6 x - 4) (3 x + 5) = (4 x - 9) (3 x + 5)

x = - \frac{5}{3}, x = - \frac{5}{2}

Decimal Notation

x = - 1.66666 \dots, x = - 2.5

Solution steps

(6 x - 4) (3 x + 5) = (4 x - 9) (3 x + 5)

Move

(4 x - 9) (3 x + 5)

to the left side

(6 x - 4) (3 x + 5) - (4 x - 9) (3 x + 5) = 0

Factor

(6 x - 4) (3 x + 5) - (4 x - 9) (3 x + 5) : (3 x + 5) (2 x + 5)

(3 x + 5) (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 5 = 0 or 2 x + 5 = 0

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - \frac{5}{2}

x^{2} = \frac{4}{9}

x^{2} = 10 x - 74

12 x^{2} - 320 x + 1600 = 0

2 x + 6 = x^{2}

x^{2} - 6 x + 3

What are the solutions to the equation (6x-4)(3x+5)=(4x-9)(3x+5) ?
The solutions to the equation (6x-4)(3x+5)=(4x-9)(3x+5) are x=-5/3 ,x=-5/2
Find the zeros of (6x-4)(3x+5)=(4x-9)(3x+5)
The zeros of (6x-4)(3x+5)=(4x-9)(3x+5) are x=-5/3 ,x=-5/2