What are the solutions to the equation 12x^2-204x+594=0 ?

The solutions to the equation 12x^2-204x+594=0 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2

Find the zeros of 12x^2-204x+594=0

The zeros of 12x^2-204x+594=0 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2

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12 x^{2} - 204 x + 594 = 0

x = \frac{17 + 91}{2}, x = \frac{17 - 91}{2}

Solution steps

12 x^{2} - 204 x + 594 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 204 ) \pm ( - 204 ) ^{2} - 4 \cdot 12 \cdot 594}{2 \cdot 12}

(- 204)^{2} - 4 \cdot 12 \cdot 594 = 1291

x_{1, 2} = \frac{- ( - 204 ) \pm 12 91}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 204 ) + 12 91}{2 \cdot 12}, x_{2} = \frac{- ( - 204 ) - 12 91}{2 \cdot 12}

x = \frac{- ( - 204 ) + 12 91}{2 \cdot 12} : \frac{17 + 91}{2}

x = \frac{- ( - 204 ) - 12 91}{2 \cdot 12} : \frac{17 - 91}{2}

The solutions to the quadratic equation are:

x = \frac{17 + 91}{2}, x = \frac{17 - 91}{2}

x, z = 3 x^{2} y + 4 x y^{2}

x^{2} + 7 x + 30 = 0

x, x^{2} - 4 y^{2} = 0

x^{2} - 20 x + 50 = 0

x^{2} - 10 + 25 = 0

What are the solutions to the equation 12x^2-204x+594=0 ?
The solutions to the equation 12x^2-204x+594=0 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2
Find the zeros of 12x^2-204x+594=0
The zeros of 12x^2-204x+594=0 are x=(17+sqrt(91))/2 ,x=(17-sqrt(91))/2