What are the solutions to the equation 4x^2=5 ?

The solutions to the equation 4x^2=5 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2

Find the zeros of 4x^2=5

The zeros of 4x^2=5 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2

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4 x^{2} = 5

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

4 x^{2} = 5

Divide both sides by

4

x^{2} = \frac{5}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{4}, x = - \frac{5}{4}

\frac{5}{4} = \frac{5}{2}

- \frac{5}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

m^{2} - 7 m + 6 = 0

(x + 3) (x - 3) = 0

x, 3 x^{2} - x y + y^{2} - 2 x + 6 y - 6 = 0

x^{2} + 12 = - 8 x

- 14 x^{2} + 3 x - 2 = 0

What are the solutions to the equation 4x^2=5 ?
The solutions to the equation 4x^2=5 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2
Find the zeros of 4x^2=5
The zeros of 4x^2=5 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2