What are the solutions to the equation -22-3x^2-2x=-3 ?

The solutions to the equation -22-3x^2-2x=-3 are x=-1/3-i(2sqrt(14))/3 ,x=-1/3+i(2sqrt(14))/3

Find the zeros of -22-3x^2-2x=-3

The zeros of -22-3x^2-2x=-3 are x=-1/3-i(2sqrt(14))/3 ,x=-1/3+i(2sqrt(14))/3

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- 22 - 3 x^{2} - 2 x = - 3

x = - \frac{1}{3} - i \frac{2 14}{3}, x = - \frac{1}{3} + i \frac{2 14}{3}

Solution steps

- 22 - 3 x^{2} - 2 x = - 3

Move

3

to the left side

- 3 x^{2} - 2 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) ( - 19 )}{2 ( - 3 )}

Simplify

(- 2)^{2} - 4 (- 3) (- 19) : 414 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 14 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 14 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 4 14 i}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 4 14 i}{2 ( - 3 )} : - \frac{1}{3} - i \frac{2 14}{3}

x = \frac{- ( - 2 ) - 4 14 i}{2 ( - 3 )} : - \frac{1}{3} + i \frac{2 14}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} - i \frac{2 14}{3}, x = - \frac{1}{3} + i \frac{2 14}{3}

- 3 x^{2} = 12

12 x^{2} - 24 = 0

9 p^{2} - 1 = 0

x^{2} - 4 x = 15

8 x - 2 = x^{2}

What are the solutions to the equation -22-3x^2-2x=-3 ?
The solutions to the equation -22-3x^2-2x=-3 are x=-1/3-i(2sqrt(14))/3 ,x=-1/3+i(2sqrt(14))/3
Find the zeros of -22-3x^2-2x=-3
The zeros of -22-3x^2-2x=-3 are x=-1/3-i(2sqrt(14))/3 ,x=-1/3+i(2sqrt(14))/3