What are the solutions to the equation -12x^2+5x+2=0 ?

The solutions to the equation -12x^2+5x+2=0 are x=-1/4 ,x= 2/3

Find the zeros of -12x^2+5x+2=0

The zeros of -12x^2+5x+2=0 are x=-1/4 ,x= 2/3

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- 12 x^{2} + 5 x + 2 = 0

x = - \frac{1}{4}, x = \frac{2}{3}

Solution steps

- 12 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 12 ) \cdot 2}{2 ( - 12 )}

5^{2} - 4 (- 12) \cdot 2 = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 ( - 12 )}, x_{2} = \frac{- 5 - 11}{2 ( - 12 )}

x = \frac{- 5 + 11}{2 ( - 12 )} : - \frac{1}{4}

x = \frac{- 5 - 11}{2 ( - 12 )} : \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = \frac{2}{3}

- 8 x^{2} + 3 x - 7 = 0

2 x^{2} - 6 = 4 x

- 12 x + 7 = 5 - 2 x^{2}

s^{2} = 0

r^{2} + 4 r + 8 = 0

What are the solutions to the equation -12x^2+5x+2=0 ?
The solutions to the equation -12x^2+5x+2=0 are x=-1/4 ,x= 2/3
Find the zeros of -12x^2+5x+2=0
The zeros of -12x^2+5x+2=0 are x=-1/4 ,x= 2/3