What are the solutions to the equation solvefor a,a^2y^2+3aby+2b^2=0 ?

The solutions to the equation solvefor a,a^2y^2+3aby+2b^2=0 are a=-b/y ,a=-(2b)/y ;\quad y\ne 0

Find the zeros of solvefor a,a^2y^2+3aby+2b^2=0

The zeros of solvefor a,a^2y^2+3aby+2b^2=0 are a=-b/y ,a=-(2b)/y ;\quad y\ne 0

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solve for

a, a^{2} y^{2} + 3 ab y + 2 b^{2} = 0

a = - \frac{b}{y}, a = - \frac{2 b}{y}; y \neq = 0

Solution steps

a^{2} y^{2} + 3 ab y + 2 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} a^{2} + 3 b y a + 2 b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 3 b y \pm ( 3 b y ) ^{2} - 4 y ^{2} \cdot 2 b ^{2}}{2 y ^{2}}

Simplify

(3 b y)^{2} - 4 y^{2} \cdot 2 b^{2} : y b

a_{1, 2} = \frac{- 3 b y \pm y b}{2 y ^{2}}; y \neq = 0

Separate the solutions

a_{1} = \frac{- 3 b y + y b}{2 y ^{2}}, a_{2} = \frac{- 3 b y - y b}{2 y ^{2}}

a = \frac{- 3 b y + y b}{2 y ^{2}} : - \frac{b}{y}

a = \frac{- 3 b y - y b}{2 y ^{2}} : - \frac{2 b}{y}

The solutions to the quadratic equation are:

a = - \frac{b}{y}, a = - \frac{2 b}{y}; y \neq = 0

c^{2} - 10 c = 0

7 d^{2} - 11 d + 4 = 4 d^{2}

x^{2} - 2 - x = 0

x^{2} - 21 x + 7 = 0

9 x^{2} + 6 = 0

What are the solutions to the equation solvefor a,a^2y^2+3aby+2b^2=0 ?
The solutions to the equation solvefor a,a^2y^2+3aby+2b^2=0 are a=-b/y ,a=-(2b)/y ;\quad y\ne 0
Find the zeros of solvefor a,a^2y^2+3aby+2b^2=0
The zeros of solvefor a,a^2y^2+3aby+2b^2=0 are a=-b/y ,a=-(2b)/y ;\quad y\ne 0