What are the solutions to the equation m^2+4m-9=0 ?

The solutions to the equation m^2+4m-9=0 are m=-2+sqrt(13),m=-2-sqrt(13)

Find the zeros of m^2+4m-9=0

The zeros of m^2+4m-9=0 are m=-2+sqrt(13),m=-2-sqrt(13)

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m^{2} + 4 m - 9 = 0

m = - 2 + 13, m = - 2 - 13

Solution steps

m^{2} + 4 m - 9 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 9) = 213

m_{1, 2} = \frac{- 4 \pm 2 13}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2 13}{2 \cdot 1}, m_{2} = \frac{- 4 - 2 13}{2 \cdot 1}

m = \frac{- 4 + 2 13}{2 \cdot 1} : - 2 + 13

m = \frac{- 4 - 2 13}{2 \cdot 1} : - 2 - 13

The solutions to the quadratic equation are:

m = - 2 + 13, m = - 2 - 13

2 x^{2} = 5 x + 2

x^{2} + 8 x + 16 = 7

0 = 2 x^{2} + 72

3 x^{2} - 12 x - 1

5^{2} + 6^{2} = x^{2}

What are the solutions to the equation m^2+4m-9=0 ?
The solutions to the equation m^2+4m-9=0 are m=-2+sqrt(13),m=-2-sqrt(13)
Find the zeros of m^2+4m-9=0
The zeros of m^2+4m-9=0 are m=-2+sqrt(13),m=-2-sqrt(13)