What are the solutions to the equation 49x^2+16=56x ?

The solutions to the equation 49x^2+16=56x are x= 4/7

Find the zeros of 49x^2+16=56x

The zeros of 49x^2+16=56x are x= 4/7

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49 x^{2} + 16 = 56 x

x = \frac{4}{7}

Decimal Notation

x = 0.57142 \dots

Solution steps

49 x^{2} + 16 = 56 x

Move

56 x

to the left side

49 x^{2} + 16 - 56 x = 0

Write in the standard form

a x^{2} + b x + c = 0

49 x^{2} - 56 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 49 \cdot 16}{2 \cdot 49}

(- 56)^{2} - 4 \cdot 49 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 56 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 56 )}{2 \cdot 49}

\frac{- ( - 56 )}{2 \cdot 49} = \frac{4}{7}

x = \frac{4}{7}

The solution to the quadratic equation is:

x = \frac{4}{7}

(y^{3} - 7 x^{4} y^{4}) + (- 10 x^{4} y^{3} + 6 y^{3} + 4 x^{4} y^{4}) - (x^{4} y^{3} + 6 x^{4} y^{4})

8 + 7

- 8 + 4 y = - 20

9 n^{2} - 64

0. 1^{3}

What are the solutions to the equation 49x^2+16=56x ?
The solutions to the equation 49x^2+16=56x are x= 4/7
Find the zeros of 49x^2+16=56x
The zeros of 49x^2+16=56x are x= 4/7