What are the solutions to the equation -2x^2+4x-6=0 ?

The solutions to the equation -2x^2+4x-6=0 are x=1-sqrt(2)i,x=1+sqrt(2)i

Find the zeros of -2x^2+4x-6=0

The zeros of -2x^2+4x-6=0 are x=1-sqrt(2)i,x=1+sqrt(2)i

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- 2 x^{2} + 4 x - 6 = 0

x = 1 - 2 i, x = 1 + 2 i

Solution steps

- 2 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 6 )}{2 ( - 2 )}

Simplify

4^{2} - 4 (- 2) (- 6) : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 ( - 2 )}, x_{2} = \frac{- 4 - 4 2 i}{2 ( - 2 )}

x = \frac{- 4 + 4 2 i}{2 ( - 2 )} : 1 - 2 i

x = \frac{- 4 - 4 2 i}{2 ( - 2 )} : 1 + 2 i

The solutions to the quadratic equation are:

x = 1 - 2 i, x = 1 + 2 i

x, x^{2} + y^{2} + z = 1

9 (5 x + 2)^{2} - 42 = 7

x, f = x^{2} y^{2} - x^{2} y^{3} + 13

3 x^{2} + 4 x - 12 = 0

x, x^{2} - 2 x = 0

What are the solutions to the equation -2x^2+4x-6=0 ?
The solutions to the equation -2x^2+4x-6=0 are x=1-sqrt(2)i,x=1+sqrt(2)i
Find the zeros of -2x^2+4x-6=0
The zeros of -2x^2+4x-6=0 are x=1-sqrt(2)i,x=1+sqrt(2)i