What are the solutions to the equation (x^2-4x+4)=0 ?

The solutions to the equation (x^2-4x+4)=0 are x=2

Find the zeros of (x^2-4x+4)=0

The zeros of (x^2-4x+4)=0 are x=2

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(x^{2} - 4 x + 4) = 0

x = 2

Solution steps

(x^{2} - 4 x + 4) = 0

Refine

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

2 x^{2} - 20 x = 0

6 x^{2} + 5 x - 21 = 0

x, (x - 1)^{2} + (y - 3)^{2} = 0

4 x^{2} - x = x^{2}

(x + 1)^{2} + x (x - 9) + 2 = 0

What are the solutions to the equation (x^2-4x+4)=0 ?
The solutions to the equation (x^2-4x+4)=0 are x=2
Find the zeros of (x^2-4x+4)=0
The zeros of (x^2-4x+4)=0 are x=2