What are the solutions to the equation 2x^2+13x-73=x^2-19 ?

The solutions to the equation 2x^2+13x-73=x^2-19 are x=(-13+sqrt(385))/2 ,x=(-13-sqrt(385))/2

Find the zeros of 2x^2+13x-73=x^2-19

The zeros of 2x^2+13x-73=x^2-19 are x=(-13+sqrt(385))/2 ,x=(-13-sqrt(385))/2

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2 x^{2} + 13 x - 73 = x^{2} - 19

x = \frac{- 13 + 385}{2}, x = \frac{- 13 - 385}{2}

Solution steps

2 x^{2} + 13 x - 73 = x^{2} - 19

Move

19

to the left side

2 x^{2} + 13 x - 54 = x^{2}

Move

x^{2}

to the left side

x^{2} + 13 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 54) = 385

x_{1, 2} = \frac{- 13 \pm 385}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 385}{2 \cdot 1}, x_{2} = \frac{- 13 - 385}{2 \cdot 1}

x = \frac{- 13 + 385}{2 \cdot 1} : \frac{- 13 + 385}{2}

x = \frac{- 13 - 385}{2 \cdot 1} : \frac{- 13 - 385}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 385}{2}, x = \frac{- 13 - 385}{2}

x, z^{3} - 3 x^{2} y + 6 x yz = 0

x^{2} - \frac{1}{5} x - 6

x^{2} - 13 = 4 x

- y^{2} + 2 y = 0

3 x^{2} = - 1

What are the solutions to the equation 2x^2+13x-73=x^2-19 ?
The solutions to the equation 2x^2+13x-73=x^2-19 are x=(-13+sqrt(385))/2 ,x=(-13-sqrt(385))/2
Find the zeros of 2x^2+13x-73=x^2-19
The zeros of 2x^2+13x-73=x^2-19 are x=(-13+sqrt(385))/2 ,x=(-13-sqrt(385))/2