What are the solutions to the equation solvefor x,x^2-y^2+4x+6y-5=0 ?

The solutions to the equation solvefor x,x^2-y^2+4x+6y-5=0 are x=y-5,x=-y+1

Find the zeros of solvefor x,x^2-y^2+4x+6y-5=0

The zeros of solvefor x,x^2-y^2+4x+6y-5=0 are x=y-5,x=-y+1

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solve for

x, x^{2} - y^{2} + 4 x + 6 y - 5 = 0

x = y - 5, x = - y + 1

Solution steps

x^{2} - y^{2} + 4 x + 6 y - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x - y^{2} + 6 y - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - y ^{2} + 6 y - 5 )}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot (- y^{2} + 6 y - 5) : 2 (y - 3)

x_{1, 2} = \frac{- 4 \pm 2 ( y - 3 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 ( y - 3 )}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 ( y - 3 )}{2 \cdot 1}

x = \frac{- 4 + 2 ( y - 3 )}{2 \cdot 1} : y - 5

x = \frac{- 4 - 2 ( y - 3 )}{2 \cdot 1} : - y + 1

The solutions to the quadratic equation are:

x = y - 5, x = - y + 1

x, 5 x^{2} + 5 y^{2} - 10 x - 10 y = - 25

[(a - 1) x + 2 a - 1] x + 3 a x = 2 a - 3

2 x^{2} + 2 x - 5 = x^{2}

x, z = 1 - x^{2}

5 x^{2} - 6 x + c = 0

What are the solutions to the equation solvefor x,x^2-y^2+4x+6y-5=0 ?
The solutions to the equation solvefor x,x^2-y^2+4x+6y-5=0 are x=y-5,x=-y+1
Find the zeros of solvefor x,x^2-y^2+4x+6y-5=0
The zeros of solvefor x,x^2-y^2+4x+6y-5=0 are x=y-5,x=-y+1