What are the solutions to the equation 3(5x+7)^2-18=48 ?

The solutions to the equation 3(5x+7)^2-18=48 are x=(sqrt(22)-7)/5 ,x=(-sqrt(22)-7)/5

Find the zeros of 3(5x+7)^2-18=48

The zeros of 3(5x+7)^2-18=48 are x=(sqrt(22)-7)/5 ,x=(-sqrt(22)-7)/5

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3 (5 x + 7)^{2} - 18 = 48

x = \frac{22 - 7}{5}, x = \frac{- 22 - 7}{5}

Solution steps

3 (5 x + 7)^{2} - 18 = 48

Move

18

to the right side

3 (5 x + 7)^{2} = 66

Divide both sides by

3

(5 x + 7)^{2} = 22

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 7 = 22 : x = \frac{22 - 7}{5}

Solve

5 x + 7 = - 22 : x = \frac{- 22 - 7}{5}

The solutions to the quadratic equation are:

x = \frac{22 - 7}{5}, x = \frac{- 22 - 7}{5}

0.000006 x^{2} - 0.02 x + 25 = 85 - 0.025 x

3 x^{2} - 4 x - 16 = 0

x, x^{2} + 9 = 0

x^{2} - 14 = - 5 x

9 x^{2} + 12 = 3 + 12 x + 5 x^{2}

What are the solutions to the equation 3(5x+7)^2-18=48 ?
The solutions to the equation 3(5x+7)^2-18=48 are x=(sqrt(22)-7)/5 ,x=(-sqrt(22)-7)/5
Find the zeros of 3(5x+7)^2-18=48
The zeros of 3(5x+7)^2-18=48 are x=(sqrt(22)-7)/5 ,x=(-sqrt(22)-7)/5