What are the solutions to the equation 2x^2+17x+24=0 ?

The solutions to the equation 2x^2+17x+24=0 are x=(-17+sqrt(97))/4 ,x=(-17-sqrt(97))/4

Find the zeros of 2x^2+17x+24=0

The zeros of 2x^2+17x+24=0 are x=(-17+sqrt(97))/4 ,x=(-17-sqrt(97))/4

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2 x^{2} + 17 x + 24 = 0

x = \frac{- 17 + 97}{4}, x = \frac{- 17 - 97}{4}

Solution steps

2 x^{2} + 17 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 2 \cdot 24}{2 \cdot 2}

1 7^{2} - 4 \cdot 2 \cdot 24 = 97

x_{1, 2} = \frac{- 17 \pm 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 17 + 97}{2 \cdot 2}, x_{2} = \frac{- 17 - 97}{2 \cdot 2}

x = \frac{- 17 + 97}{2 \cdot 2} : \frac{- 17 + 97}{4}

x = \frac{- 17 - 97}{2 \cdot 2} : \frac{- 17 - 97}{4}

The solutions to the quadratic equation are:

x = \frac{- 17 + 97}{4}, x = \frac{- 17 - 97}{4}

x^{2} - \frac{1}{4} x + 2

4 (6 - 4 x)^{2} = 49

y^{2} + 3 y - 28 = 0

x^{2} = \frac{1}{16}

x^{2} - 3 = 1

What are the solutions to the equation 2x^2+17x+24=0 ?
The solutions to the equation 2x^2+17x+24=0 are x=(-17+sqrt(97))/4 ,x=(-17-sqrt(97))/4
Find the zeros of 2x^2+17x+24=0
The zeros of 2x^2+17x+24=0 are x=(-17+sqrt(97))/4 ,x=(-17-sqrt(97))/4