What are the solutions to the equation 5m^2-7m=5 ?

The solutions to the equation 5m^2-7m=5 are m=(7+sqrt(149))/(10),m=(7-sqrt(149))/(10)

Find the zeros of 5m^2-7m=5

The zeros of 5m^2-7m=5 are m=(7+sqrt(149))/(10),m=(7-sqrt(149))/(10)

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5 m^{2} - 7 m = 5

m = \frac{7 + 149}{10}, m = \frac{7 - 149}{10}

Decimal Notation

m = 1.92065 \dots, m = - 0.52065 \dots

Solution steps

5 m^{2} - 7 m = 5

Move

5

to the left side

5 m^{2} - 7 m - 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 5) = 149

m_{1, 2} = \frac{- ( - 7 ) \pm 149}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 149}{2 \cdot 5}, m_{2} = \frac{- ( - 7 ) - 149}{2 \cdot 5}

m = \frac{- ( - 7 ) + 149}{2 \cdot 5} : \frac{7 + 149}{10}

m = \frac{- ( - 7 ) - 149}{2 \cdot 5} : \frac{7 - 149}{10}

The solutions to the quadratic equation are:

m = \frac{7 + 149}{10}, m = \frac{7 - 149}{10}

3 x^{2} + 20 x + 12 = 0

x, x^{2} - 9 = 0

2 r^{2} + 7 r - 1 = - 3 r^{2}

3 r^{2} - 4 r - 5 = 0

3 x^{2} + 7 x - 3 = 0

What are the solutions to the equation 5m^2-7m=5 ?
The solutions to the equation 5m^2-7m=5 are m=(7+sqrt(149))/(10),m=(7-sqrt(149))/(10)
Find the zeros of 5m^2-7m=5
The zeros of 5m^2-7m=5 are m=(7+sqrt(149))/(10),m=(7-sqrt(149))/(10)