What are the solutions to the equation x^2+40=4 ?

The solutions to the equation x^2+40=4 are x=6i,x=-6i

Find the zeros of x^2+40=4

The zeros of x^2+40=4 are x=6i,x=-6i

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x^{2} + 40 = 4

x = 6 i, x = - 6 i

Solution steps

x^{2} + 40 = 4

Move

40

to the right side

x^{2} = - 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 36, x = - - 36

- 36 = 6 i

- - 36 = - 6 i

x = 6 i, x = - 6 i

100 x^{2} - 25 = 0

(x - 7)^{2} = 32

- 2 x^{2} - 6 x + 8 = 0

16 x^{2} + 40 x + 25 = 0

x^{2} - 10 x - 75 = 0

What are the solutions to the equation x^2+40=4 ?
The solutions to the equation x^2+40=4 are x=6i,x=-6i
Find the zeros of x^2+40=4
The zeros of x^2+40=4 are x=6i,x=-6i