What are the solutions to the equation x^2+12x=45 ?

The solutions to the equation x^2+12x=45 are x=3,x=-15

Find the zeros of x^2+12x=45

The zeros of x^2+12x=45 are x=3,x=-15

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x^{2} + 12 x = 45

x = 3, x = - 15

Solution steps

x^{2} + 12 x = 45

Move

45

to the left side

x^{2} + 12 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 45) = 18

x_{1, 2} = \frac{- 12 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 18}{2 \cdot 1}, x_{2} = \frac{- 12 - 18}{2 \cdot 1}

x = \frac{- 12 + 18}{2 \cdot 1} : 3

x = \frac{- 12 - 18}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 3, x = - 15

t^{2} - 4 t - 12 = 0

x, x^{2} y + x y^{2} = 3 x

x^{2} - 8 = 8

r^{2} - 8 r = - 8

12 x^{2} - 17 x + 6 = 0

What are the solutions to the equation x^2+12x=45 ?
The solutions to the equation x^2+12x=45 are x=3,x=-15
Find the zeros of x^2+12x=45
The zeros of x^2+12x=45 are x=3,x=-15