What are the solutions to the equation 25x^2-50x+26=0 ?

The solutions to the equation 25x^2-50x+26=0 are x=1+i 1/5 ,x=1-i 1/5

Find the zeros of 25x^2-50x+26=0

The zeros of 25x^2-50x+26=0 are x=1+i 1/5 ,x=1-i 1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} - 50 x + 26 = 0

x = 1 + i \frac{1}{5}, x = 1 - i \frac{1}{5}

Solution steps

25 x^{2} - 50 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 25 \cdot 26}{2 \cdot 25}

Simplify

(- 50)^{2} - 4 \cdot 25 \cdot 26 : 10 i

x_{1, 2} = \frac{- ( - 50 ) \pm 10 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 50 ) + 10 i}{2 \cdot 25}, x_{2} = \frac{- ( - 50 ) - 10 i}{2 \cdot 25}

x = \frac{- ( - 50 ) + 10 i}{2 \cdot 25} : 1 + i \frac{1}{5}

x = \frac{- ( - 50 ) - 10 i}{2 \cdot 25} : 1 - i \frac{1}{5}

The solutions to the quadratic equation are:

x = 1 + i \frac{1}{5}, x = 1 - i \frac{1}{5}

16 x^{2} + 6 x = 0

4 x^{2} - 23 x - 6 = 0

b^{2} + 4 b - 21 = 0

x^{2} - 15 x + 26 = 0

9 x^{2} + 79 = - 18 x

What are the solutions to the equation 25x^2-50x+26=0 ?
The solutions to the equation 25x^2-50x+26=0 are x=1+i 1/5 ,x=1-i 1/5
Find the zeros of 25x^2-50x+26=0
The zeros of 25x^2-50x+26=0 are x=1+i 1/5 ,x=1-i 1/5