What are the solutions to the equation 2x^2-40=-140 ?

The solutions to the equation 2x^2-40=-140 are x=sqrt(2)*5i,x=-sqrt(2)*5i

Find the zeros of 2x^2-40=-140

The zeros of 2x^2-40=-140 are x=sqrt(2)*5i,x=-sqrt(2)*5i

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2 x^{2} - 40 = - 140

x = 2 \cdot 5 i, x = - 2 \cdot 5 i

Solution steps

2 x^{2} - 40 = - 140

Move

40

to the right side

2 x^{2} = - 100

Divide both sides by

2

x^{2} = - 50

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 50, x = - - 50

- 50 = 2 \cdot 5 i

- - 50 = - 2 \cdot 5 i

x = 2 \cdot 5 i, x = - 2 \cdot 5 i

2^{2} + 4^{2} = x^{2}

8 x^{2} = 72

x^{2} - 6 x + 9 = 64

x^{2} + 7 x + 15 = 0

(x + 7)^{2} = 9

What are the solutions to the equation 2x^2-40=-140 ?
The solutions to the equation 2x^2-40=-140 are x=sqrt(2)*5i,x=-sqrt(2)*5i
Find the zeros of 2x^2-40=-140
The zeros of 2x^2-40=-140 are x=sqrt(2)*5i,x=-sqrt(2)*5i