What are the solutions to the equation (x+1)^2=11 ?

The solutions to the equation (x+1)^2=11 are x=sqrt(11)-1,x=-sqrt(11)-1

Find the zeros of (x+1)^2=11

The zeros of (x+1)^2=11 are x=sqrt(11)-1,x=-sqrt(11)-1

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(x + 1)^{2} = 11

x = 11 - 1, x = - 11 - 1

Decimal Notation

x = 2.31662 \dots, x = - 4.31662 \dots

Solution steps

(x + 1)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 11 : x = 11 - 1

Solve

x + 1 = - 11 : x = - 11 - 1

The solutions to the quadratic equation are:

x = 11 - 1, x = - 11 - 1

x^{2} + 13 = 17

- x^{2} + 12 x - 36 = 0

x^{2} + 4 x + 7 = 15

8 x^{2} - 2 x - 5 = 0

0 = x^{2} - 3

What are the solutions to the equation (x+1)^2=11 ?
The solutions to the equation (x+1)^2=11 are x=sqrt(11)-1,x=-sqrt(11)-1
Find the zeros of (x+1)^2=11
The zeros of (x+1)^2=11 are x=sqrt(11)-1,x=-sqrt(11)-1