What are the solutions to the equation x^2+9x-1=0 ?

The solutions to the equation x^2+9x-1=0 are x=(-9+sqrt(85))/2 ,x=(-9-sqrt(85))/2

Find the zeros of x^2+9x-1=0

The zeros of x^2+9x-1=0 are x=(-9+sqrt(85))/2 ,x=(-9-sqrt(85))/2

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x^{2} + 9 x - 1 = 0

x = \frac{- 9 + 85}{2}, x = \frac{- 9 - 85}{2}

Decimal Notation

x = 0.10977 \dots, x = - 9.10977 \dots

Solution steps

x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 1) = 85

x_{1, 2} = \frac{- 9 \pm 85}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 85}{2 \cdot 1}, x_{2} = \frac{- 9 - 85}{2 \cdot 1}

x = \frac{- 9 + 85}{2 \cdot 1} : \frac{- 9 + 85}{2}

x = \frac{- 9 - 85}{2 \cdot 1} : \frac{- 9 - 85}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 85}{2}, x = \frac{- 9 - 85}{2}

- 2 x - 2 > 6

\frac{x}{3} + \frac{x}{5} = \frac{8}{15}

x^{2} < x + 2

6 (x - 2) = - 18

(3 x^{\frac{2}{3}})^{- 1}

What are the solutions to the equation x^2+9x-1=0 ?
The solutions to the equation x^2+9x-1=0 are x=(-9+sqrt(85))/2 ,x=(-9-sqrt(85))/2
Find the zeros of x^2+9x-1=0
The zeros of x^2+9x-1=0 are x=(-9+sqrt(85))/2 ,x=(-9-sqrt(85))/2