What are the solutions to the equation 12x^2+9x-2=-17 ?

The solutions to the equation 12x^2+9x-2=-17 are x=-3/8+i(sqrt(71))/8 ,x=-3/8-i(sqrt(71))/8

Find the zeros of 12x^2+9x-2=-17

The zeros of 12x^2+9x-2=-17 are x=-3/8+i(sqrt(71))/8 ,x=-3/8-i(sqrt(71))/8

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12 x^{2} + 9 x - 2 = - 17

x = - \frac{3}{8} + i \frac{71}{8}, x = - \frac{3}{8} - i \frac{71}{8}

Solution steps

12 x^{2} + 9 x - 2 = - 17

Move

17

to the left side

12 x^{2} + 9 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 12 \cdot 15}{2 \cdot 12}

Simplify

9^{2} - 4 \cdot 12 \cdot 15 : 371 i

x_{1, 2} = \frac{- 9 \pm 3 71 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 9 + 3 71 i}{2 \cdot 12}, x_{2} = \frac{- 9 - 3 71 i}{2 \cdot 12}

x = \frac{- 9 + 3 71 i}{2 \cdot 12} : - \frac{3}{8} + i \frac{71}{8}

x = \frac{- 9 - 3 71 i}{2 \cdot 12} : - \frac{3}{8} - i \frac{71}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} + i \frac{71}{8}, x = - \frac{3}{8} - i \frac{71}{8}

3 y^{2} - 1 = 0

x^{2} + 24 x = 52

k^{2} + 8 = 8

x^{2} - x - 132 = 0

x^{2} - 16 x = 80

What are the solutions to the equation 12x^2+9x-2=-17 ?
The solutions to the equation 12x^2+9x-2=-17 are x=-3/8+i(sqrt(71))/8 ,x=-3/8-i(sqrt(71))/8
Find the zeros of 12x^2+9x-2=-17
The zeros of 12x^2+9x-2=-17 are x=-3/8+i(sqrt(71))/8 ,x=-3/8-i(sqrt(71))/8