What are the solutions to the equation x^2-5x-25=0 ?

The solutions to the equation x^2-5x-25=0 are x=(5+5sqrt(5))/2 ,x=(5-5sqrt(5))/2

Find the zeros of x^2-5x-25=0

The zeros of x^2-5x-25=0 are x=(5+5sqrt(5))/2 ,x=(5-5sqrt(5))/2

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x^{2} - 5 x - 25 = 0

x = \frac{5 + 5 5}{2}, x = \frac{5 - 5 5}{2}

Decimal Notation

x = 8.09016 \dots, x = - 3.09016 \dots

Solution steps

x^{2} - 5 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 25) = 55

x_{1, 2} = \frac{- ( - 5 ) \pm 5 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5 5}{2 \cdot 1} : \frac{5 + 5 5}{2}

x = \frac{- ( - 5 ) - 5 5}{2 \cdot 1} : \frac{5 - 5 5}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 5 5}{2}, x = \frac{5 - 5 5}{2}

x^{2} - 4 x - 21 = 0

x^{2} + 2 x + 1

x^{2} + 2 x + 4

(x - 1)^{2} = 10

x^{2} + 4 x - 13 = - 7

What are the solutions to the equation x^2-5x-25=0 ?
The solutions to the equation x^2-5x-25=0 are x=(5+5sqrt(5))/2 ,x=(5-5sqrt(5))/2
Find the zeros of x^2-5x-25=0
The zeros of x^2-5x-25=0 are x=(5+5sqrt(5))/2 ,x=(5-5sqrt(5))/2