What are the solutions to the equation (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0 ?

The solutions to the equation (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0 are x=2+sqrt(2),x=(sqrt(2)-6)/(17)

Find the zeros of (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0

The zeros of (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0 are x=2+sqrt(2),x=(sqrt(2)-6)/(17)

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(5 - 22) x^{2} - (4 + 22) x - 2 = 0

x = 2 + 2, x = \frac{2 - 6}{17}

Decimal Notation

x = 3.41421 \dots, x = - 0.26975 \dots

Solution steps

(5 - 22) x^{2} - (4 + 22) x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 - 2 2 ) \pm ( - 4 - 2 2 ) ^{2} - 4 ( 5 - 2 2 ) ( - 2 )}{2 ( 5 - 2 2 )}

(- 4 - 22)^{2} - 4 (5 - 22) (- 2) = 8

x_{1, 2} = \frac{- ( - 4 - 2 2 ) \pm 8}{2 ( 5 - 2 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 - 2 2 ) + 8}{2 ( 5 - 2 2 )}, x_{2} = \frac{- ( - 4 - 2 2 ) - 8}{2 ( 5 - 2 2 )}

x = \frac{- ( - 4 - 2 2 ) + 8}{2 ( 5 - 2 2 )} : 2 + 2

x = \frac{- ( - 4 - 2 2 ) - 8}{2 ( 5 - 2 2 )} : \frac{2 - 6}{17}

The solutions to the quadratic equation are:

x = 2 + 2, x = \frac{2 - 6}{17}

9 x^{2} + 12 x + 5 = 0

x^{2} + 3 x - 16 = 0

x^{2} - 2 a x - 3 a^{2} = 0

4 x^{2} = 32 x - 67

(n + 4)^{2} = 2 n^{2} + 14 n + 24

What are the solutions to the equation (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0 ?
The solutions to the equation (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0 are x=2+sqrt(2),x=(sqrt(2)-6)/(17)
Find the zeros of (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0
The zeros of (5-2sqrt(2))x^2-(4+2sqrt(2))x-2=0 are x=2+sqrt(2),x=(sqrt(2)-6)/(17)