What are the solutions to the equation x^2+9x-1=3x-10 ?

The solutions to the equation x^2+9x-1=3x-10 are x=-3

Find the zeros of x^2+9x-1=3x-10

The zeros of x^2+9x-1=3x-10 are x=-3

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x^{2} + 9 x - 1 = 3 x - 10

x = - 3

Solution steps

x^{2} + 9 x - 1 = 3 x - 10

Move

10

to the left side

x^{2} + 9 x + 9 = 3 x

Move

3 x

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

x^{2} + 10 x - 80 = 0

x^{2} - 2 x + 1 = 81

x, x^{2} y + y^{2} x = - 2

x^{2} + 5 x + 20 = 0

(z + 7)^{2} = - 9

What are the solutions to the equation x^2+9x-1=3x-10 ?
The solutions to the equation x^2+9x-1=3x-10 are x=-3
Find the zeros of x^2+9x-1=3x-10
The zeros of x^2+9x-1=3x-10 are x=-3