What are the solutions to the equation (x^2-6)/2-(x^2+4)/4 =5 ?

The solutions to the equation (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6

Find the zeros of (x^2-6)/2-(x^2+4)/4 =5

The zeros of (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6

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\frac{x ^{2} - 6}{2} - \frac{x ^{2} + 4}{4} = 5

x = 6, x = - 6

Solution steps

\frac{x ^{2} - 6}{2} - \frac{x ^{2} + 4}{4} = 5

Multiply by LCM

2 (x^{2} - 6) - (x^{2} + 4) = 20

Expand

2 (x^{2} - 6) - (x^{2} + 4) : x^{2} - 16

x^{2} - 16 = 20

Move

16

to the right side

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

- 0.3 x - 7.2 \leq 0.1 x + 0.4

x^{4} - 10 x + 9

1018

8 = - x^{2} - x

\frac{3 x}{x + 4} \geq 0

What are the solutions to the equation (x^2-6)/2-(x^2+4)/4 =5 ?
The solutions to the equation (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6
Find the zeros of (x^2-6)/2-(x^2+4)/4 =5
The zeros of (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6