What are the solutions to the equation 3x^2+22x-16=0 ?

The solutions to the equation 3x^2+22x-16=0 are x= 2/3 ,x=-8

Find the zeros of 3x^2+22x-16=0

The zeros of 3x^2+22x-16=0 are x= 2/3 ,x=-8

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3 x^{2} + 22 x - 16 = 0

x = \frac{2}{3}, x = - 8

Decimal Notation

x = 0.66666 \dots, x = - 8

Solution steps

3 x^{2} + 22 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

2 2^{2} - 4 \cdot 3 (- 16) = 26

x_{1, 2} = \frac{- 22 \pm 26}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 22 + 26}{2 \cdot 3}, x_{2} = \frac{- 22 - 26}{2 \cdot 3}

x = \frac{- 22 + 26}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 22 - 26}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 8

x^{2} - 22 x + 120 = 0

3 x^{2} - 3 x + 8 = 0

- 5 x^{2} - 87 x - 391 = 3 x - 6

x^{2} + 0.9 x + 0.81 = 0

4 x^{2} - x - 6 = 0

What are the solutions to the equation 3x^2+22x-16=0 ?
The solutions to the equation 3x^2+22x-16=0 are x= 2/3 ,x=-8
Find the zeros of 3x^2+22x-16=0
The zeros of 3x^2+22x-16=0 are x= 2/3 ,x=-8