What are the solutions to the equation m^2+2m-24=0 ?

The solutions to the equation m^2+2m-24=0 are m=4,m=-6

Find the zeros of m^2+2m-24=0

The zeros of m^2+2m-24=0 are m=4,m=-6

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m^{2} + 2 m - 24 = 0

m = 4, m = - 6

Solution steps

m^{2} + 2 m - 24 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

m_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 10}{2 \cdot 1}, m_{2} = \frac{- 2 - 10}{2 \cdot 1}

m = \frac{- 2 + 10}{2 \cdot 1} : 4

m = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = 4, m = - 6

x^{2} + 18 x = 4 x - 49

A, y = A x + A^{2} - B e^{- x}

x, 5 x^{2} + 2 x^{2} y + y^{2} = 8

3 x^{2} + 6 x + 8 = 0

x^{2} + 8 x + 21 = 0

What are the solutions to the equation m^2+2m-24=0 ?
The solutions to the equation m^2+2m-24=0 are m=4,m=-6
Find the zeros of m^2+2m-24=0
The zeros of m^2+2m-24=0 are m=4,m=-6