What are the solutions to the equation y^2-9y+8=0 ?

The solutions to the equation y^2-9y+8=0 are y=8,y=1

Find the zeros of y^2-9y+8=0

The zeros of y^2-9y+8=0 are y=8,y=1

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y^{2} - 9 y + 8 = 0

y = 8, y = 1

Solution steps

y^{2} - 9 y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

y_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, y_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

y = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

y = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

y = 8, y = 1

x, x^{2} + y^{2} - 6 x + 2 y + 12 = 0

(x + 1) (x - 1) = 3

6 x^{2} - 5 x = 6

7 x^{2} + 35 x = 0

- 6 x^{2} + 108 x - 1368 = 0

What are the solutions to the equation y^2-9y+8=0 ?
The solutions to the equation y^2-9y+8=0 are y=8,y=1
Find the zeros of y^2-9y+8=0
The zeros of y^2-9y+8=0 are y=8,y=1