What are the solutions to the equation (x^2)/(10)-x/5+2=0 ?

The solutions to the equation (x^2)/(10)-x/5+2=0 are x=1+sqrt(19)i,x=1-sqrt(19)i

Find the zeros of (x^2)/(10)-x/5+2=0

The zeros of (x^2)/(10)-x/5+2=0 are x=1+sqrt(19)i,x=1-sqrt(19)i

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\frac{x ^{2}}{10} - \frac{x}{5} + 2 = 0

x = 1 + 19 i, x = 1 - 19 i

Solution steps

\frac{x ^{2}}{10} - \frac{x}{5} + 2 = 0

Find Least Common Multiplier of

10, 5 : 10

Multiply by LCM=

10

\frac{x ^{2}}{10} \cdot 10 - \frac{x}{5} \cdot 10 + 2 \cdot 10 = 0 \cdot 10

Simplify

x^{2} - 2 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 20 : 219 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 19 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 19 i}{2 \cdot 1} : 1 + 19 i

x = \frac{- ( - 2 ) - 2 19 i}{2 \cdot 1} : 1 - 19 i

The solutions to the quadratic equation are:

x = 1 + 19 i, x = 1 - 19 i

x, x^{2} = - y^{2}

3 = 3 x^{2}

16 x - x^{2} - 48 = 0

s^{2} - 4 s + 13 = 0

x (x - 3) = 5 (x - 2) + 1

What are the solutions to the equation (x^2)/(10)-x/5+2=0 ?
The solutions to the equation (x^2)/(10)-x/5+2=0 are x=1+sqrt(19)i,x=1-sqrt(19)i
Find the zeros of (x^2)/(10)-x/5+2=0
The zeros of (x^2)/(10)-x/5+2=0 are x=1+sqrt(19)i,x=1-sqrt(19)i