What are the solutions to the equation 3x^2-16x+12=0 ?

The solutions to the equation 3x^2-16x+12=0 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3

Find the zeros of 3x^2-16x+12=0

The zeros of 3x^2-16x+12=0 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3

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3 x^{2} - 16 x + 12 = 0

x = \frac{2 ( 4 + 7 )}{3}, x = \frac{2 ( 4 - 7 )}{3}

Decimal Notation

x = 4.43050 \dots, x = 0.90283 \dots

Solution steps

3 x^{2} - 16 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 12 = 47

x_{1, 2} = \frac{- ( - 16 ) \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 7}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 4 7}{2 \cdot 3}

x = \frac{- ( - 16 ) + 4 7}{2 \cdot 3} : \frac{2 ( 4 + 7 )}{3}

x = \frac{- ( - 16 ) - 4 7}{2 \cdot 3} : \frac{2 ( 4 - 7 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 4 + 7 )}{3}, x = \frac{2 ( 4 - 7 )}{3}

8^{2} + x^{2} = 1 2^{2}

x^{2} - 3 x - 108 = 0

- x^{2} = 9

3 x^{2} + 3 x - 3 = 0

2 n^{2} + 3 n - 9 = 0

What are the solutions to the equation 3x^2-16x+12=0 ?
The solutions to the equation 3x^2-16x+12=0 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3
Find the zeros of 3x^2-16x+12=0
The zeros of 3x^2-16x+12=0 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3