What are the solutions to the equation 4-x^2=3x ?

The solutions to the equation 4-x^2=3x are x=-4,x=1

Find the zeros of 4-x^2=3x

The zeros of 4-x^2=3x are x=-4,x=1

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4 - x^{2} = 3 x

x = - 4, x = 1

Solution steps

4 - x^{2} = 3 x

Move

3 x

to the left side

4 - x^{2} - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 4 = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 5}{2 ( - 1 )} : - 4

x = \frac{- ( - 3 ) - 5}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 4, x = 1

(x + 7)^{2} = 25

3 - 2 x - x^{2}

8 q^{2} = - 2 q + 1

4 x^{2} - 11 x - 3 = 0

x^{2} - \frac{3}{2} x = 1

What are the solutions to the equation 4-x^2=3x ?
The solutions to the equation 4-x^2=3x are x=-4,x=1
Find the zeros of 4-x^2=3x
The zeros of 4-x^2=3x are x=-4,x=1