What are the solutions to the equation x^2-4x=49 ?

The solutions to the equation x^2-4x=49 are x=2+sqrt(53),x=2-sqrt(53)

Find the zeros of x^2-4x=49

The zeros of x^2-4x=49 are x=2+sqrt(53),x=2-sqrt(53)

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x^{2} - 4 x = 49

x = 2 + 53, x = 2 - 53

Decimal Notation

x = 9.28010 \dots, x = - 5.28010 \dots

Solution steps

x^{2} - 4 x = 49

Move

49

to the left side

x^{2} - 4 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 49) = 253

x_{1, 2} = \frac{- ( - 4 ) \pm 2 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 53}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 53}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 53}{2 \cdot 1} : 2 + 53

x = \frac{- ( - 4 ) - 2 53}{2 \cdot 1} : 2 - 53

The solutions to the quadratic equation are:

x = 2 + 53, x = 2 - 53

3 (y - 2) = y - 6

lo g_{4} (27)

(5 - 8 i)^{2}

2 x + 1 < - 9

4 (v + 1) + 5 = 6 (v - 1) + v

What are the solutions to the equation x^2-4x=49 ?
The solutions to the equation x^2-4x=49 are x=2+sqrt(53),x=2-sqrt(53)
Find the zeros of x^2-4x=49
The zeros of x^2-4x=49 are x=2+sqrt(53),x=2-sqrt(53)