What are the solutions to the equation x^2-27x=0 ?

The solutions to the equation x^2-27x=0 are x=27,x=0

Find the zeros of x^2-27x=0

The zeros of x^2-27x=0 are x=27,x=0

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x^{2} - 27 x = 0

x = 27, x = 0

Solution steps

x^{2} - 27 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 27)^{2} - 4 \cdot 1 \cdot 0 = 27

x_{1, 2} = \frac{- ( - 27 ) \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 27}{2 \cdot 1}, x_{2} = \frac{- ( - 27 ) - 27}{2 \cdot 1}

x = \frac{- ( - 27 ) + 27}{2 \cdot 1} : 27

x = \frac{- ( - 27 ) - 27}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 27, x = 0

1 \frac{4}{15} - \frac{2}{3} x^{2} = - 12 \frac{7}{30}

4 x^{2} + 4 x + 1 = 16

2 x^{2} + 12 x - 80 = 0

3 x^{2} - 57 = 24 x - 9

What are the solutions to the equation x^2-27x=0 ?
The solutions to the equation x^2-27x=0 are x=27,x=0
Find the zeros of x^2-27x=0
The zeros of x^2-27x=0 are x=27,x=0