What are the solutions to the equation 16x^2-8x+145=0 ?

The solutions to the equation 16x^2-8x+145=0 are x= 1/4+3i,x= 1/4-3i

Find the zeros of 16x^2-8x+145=0

The zeros of 16x^2-8x+145=0 are x= 1/4+3i,x= 1/4-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} - 8 x + 145 = 0

x = \frac{1}{4} + 3 i, x = \frac{1}{4} - 3 i

Solution steps

16 x^{2} - 8 x + 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 \cdot 145}{2 \cdot 16}

Simplify

(- 8)^{2} - 4 \cdot 16 \cdot 145 : 96 i

x_{1, 2} = \frac{- ( - 8 ) \pm 96 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 96 i}{2 \cdot 16}, x_{2} = \frac{- ( - 8 ) - 96 i}{2 \cdot 16}

x = \frac{- ( - 8 ) + 96 i}{2 \cdot 16} : \frac{1}{4} + 3 i

x = \frac{- ( - 8 ) - 96 i}{2 \cdot 16} : \frac{1}{4} - 3 i

The solutions to the quadratic equation are:

x = \frac{1}{4} + 3 i, x = \frac{1}{4} - 3 i

- 4 x^{2} + 3 x = 0

x^{2} + (a + 3) x + a + 2 = 0

12 x^{2} - 300 = 0

7 x^{2} = 100

x^{2} - 12 + 36 = 0

What are the solutions to the equation 16x^2-8x+145=0 ?
The solutions to the equation 16x^2-8x+145=0 are x= 1/4+3i,x= 1/4-3i
Find the zeros of 16x^2-8x+145=0
The zeros of 16x^2-8x+145=0 are x= 1/4+3i,x= 1/4-3i