What are the solutions to the equation 2x^2+4x-10=0 ?

The solutions to the equation 2x^2+4x-10=0 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of 2x^2+4x-10=0

The zeros of 2x^2+4x-10=0 are x=-1+sqrt(6),x=-1-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 4 x - 10 = 0

x = - 1 + 6, x = - 1 - 6

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

2 x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 10) = 46

x_{1, 2} = \frac{- 4 \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 6}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 6}{2 \cdot 2}

x = \frac{- 4 + 4 6}{2 \cdot 2} : - 1 + 6

x = \frac{- 4 - 4 6}{2 \cdot 2} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

\frac{( x + 2 ) ^{2}}{5} + \frac{( x - 2 ) ^{2}}{3} = \frac{16}{3}

x^{2} - x - 1

(x - 5)^{2} = - 25

2 x^{2} - 7 x + 5

12 x^{2} - 30 x = 0

What are the solutions to the equation 2x^2+4x-10=0 ?
The solutions to the equation 2x^2+4x-10=0 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of 2x^2+4x-10=0
The zeros of 2x^2+4x-10=0 are x=-1+sqrt(6),x=-1-sqrt(6)