What are the solutions to the equation 3x^2-21x+36=0 ?

The solutions to the equation 3x^2-21x+36=0 are x=4,x=3

Find the zeros of 3x^2-21x+36=0

The zeros of 3x^2-21x+36=0 are x=4,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 21 x + 36 = 0

x = 4, x = 3

Solution steps

3 x^{2} - 21 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 3 \cdot 36}{2 \cdot 3}

(- 21)^{2} - 4 \cdot 3 \cdot 36 = 3

x_{1, 2} = \frac{- ( - 21 ) \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 3}{2 \cdot 3}, x_{2} = \frac{- ( - 21 ) - 3}{2 \cdot 3}

x = \frac{- ( - 21 ) + 3}{2 \cdot 3} : 4

x = \frac{- ( - 21 ) - 3}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

x = 4, x = 3

y^{2} + 6 y + 5 = 0

2 x^{2} - 3 = - 5 x

3 x^{2} + 4 = 5 x

9 = x^{2} - 16 x + 64

x, z = x y^{6} - 3 x + 8 x^{2} y^{2} - y^{2}

What are the solutions to the equation 3x^2-21x+36=0 ?
The solutions to the equation 3x^2-21x+36=0 are x=4,x=3
Find the zeros of 3x^2-21x+36=0
The zeros of 3x^2-21x+36=0 are x=4,x=3