What are the solutions to the equation -4x^2-x+1=0 ?

The solutions to the equation -4x^2-x+1=0 are x=-(1+sqrt(17))/8 ,x=(sqrt(17)-1)/8

Find the zeros of -4x^2-x+1=0

The zeros of -4x^2-x+1=0 are x=-(1+sqrt(17))/8 ,x=(sqrt(17)-1)/8

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- 4 x^{2} - x + 1 = 0

x = - \frac{1 + 17}{8}, x = \frac{17 - 1}{8}

Decimal Notation

x = - 0.64038 \dots, x = 0.39038 \dots

Solution steps

- 4 x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 4 ) \cdot 1}{2 ( - 4 )}

(- 1)^{2} - 4 (- 4) \cdot 1 = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 ( - 4 )}, x_{2} = \frac{- ( - 1 ) - 17}{2 ( - 4 )}

x = \frac{- ( - 1 ) + 17}{2 ( - 4 )} : - \frac{1 + 17}{8}

x = \frac{- ( - 1 ) - 17}{2 ( - 4 )} : \frac{17 - 1}{8}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{8}, x = \frac{17 - 1}{8}

13 x^{2} + 39 = 0

x^{2} - 12 x = - 18

(2 x + 1)^{2} - (3 x + 5) (2 x - 1) + 3 (x^{2} + 3 x - 4) = 2 x - 1

- x^{2} + 4 x - 6 = 0

9 y^{2} - 16 = 0

What are the solutions to the equation -4x^2-x+1=0 ?
The solutions to the equation -4x^2-x+1=0 are x=-(1+sqrt(17))/8 ,x=(sqrt(17)-1)/8
Find the zeros of -4x^2-x+1=0
The zeros of -4x^2-x+1=0 are x=-(1+sqrt(17))/8 ,x=(sqrt(17)-1)/8