What are the solutions to the equation 9x^2-x-8=0 ?

The solutions to the equation 9x^2-x-8=0 are x=1,x=-8/9

Find the zeros of 9x^2-x-8=0

The zeros of 9x^2-x-8=0 are x=1,x=-8/9

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9 x^{2} - x - 8 = 0

x = 1, x = - \frac{8}{9}

Decimal Notation

x = 1, x = - 0.88888 \dots

Solution steps

9 x^{2} - x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

(- 1)^{2} - 4 \cdot 9 (- 8) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 9}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 9}

x = \frac{- ( - 1 ) + 17}{2 \cdot 9} : 1

x = \frac{- ( - 1 ) - 17}{2 \cdot 9} : - \frac{8}{9}

The solutions to the quadratic equation are:

x = 1, x = - \frac{8}{9}

x^{2} - 4 x - 36 = 0

3 x^{2} + 8 = 0

5 + 9 + 13 + (4 n + 1) = n (2 n + 3)

x^{2} + 5 = 50

115 = - 6 + n^{2}

What are the solutions to the equation 9x^2-x-8=0 ?
The solutions to the equation 9x^2-x-8=0 are x=1,x=-8/9
Find the zeros of 9x^2-x-8=0
The zeros of 9x^2-x-8=0 are x=1,x=-8/9