What are the solutions to the equation 7x+4x^2+4=2 ?

The solutions to the equation 7x+4x^2+4=2 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8

Find the zeros of 7x+4x^2+4=2

The zeros of 7x+4x^2+4=2 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x + 4 x^{2} + 4 = 2

x = \frac{- 7 + 17}{8}, x = \frac{- 7 - 17}{8}

Decimal Notation

x = - 0.35961 \dots, x = - 1.39038 \dots

Solution steps

7 x + 4 x^{2} + 4 = 2

Move

2

to the left side

4 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

7^{2} - 4 \cdot 4 \cdot 2 = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 4}, x_{2} = \frac{- 7 - 17}{2 \cdot 4}

x = \frac{- 7 + 17}{2 \cdot 4} : \frac{- 7 + 17}{8}

x = \frac{- 7 - 17}{2 \cdot 4} : \frac{- 7 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 7 + 17}{8}, x = \frac{- 7 - 17}{8}

1^{2} + 2^{2} = x^{2}

6 x = x^{2} + 7

7 x^{2} - 16 x + 9 = 0

3 m^{2} - m = 0

2 (3 x^{2} + 4) = 19 x

What are the solutions to the equation 7x+4x^2+4=2 ?
The solutions to the equation 7x+4x^2+4=2 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8
Find the zeros of 7x+4x^2+4=2
The zeros of 7x+4x^2+4=2 are x=(-7+sqrt(17))/8 ,x=(-7-sqrt(17))/8