What are the solutions to the equation x^2+4=-4x ?

The solutions to the equation x^2+4=-4x are x=-2

Find the zeros of x^2+4=-4x

The zeros of x^2+4=-4x are x=-2

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x^{2} + 4 = - 4 x

x = - 2

Solution steps

x^{2} + 4 = - 4 x

Move

4 x

to the left side

x^{2} + 4 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

0 = 3 x^{2} - 2 x - 2

8^{2} + 8^{2} = x^{2}

y^{2} + 8 y + 13 = 0

\frac{p ^{2}}{16} = \frac{1}{4} p^{2}

25 (3 x + 4)^{2} - 11 = 38

What are the solutions to the equation x^2+4=-4x ?
The solutions to the equation x^2+4=-4x are x=-2
Find the zeros of x^2+4=-4x
The zeros of x^2+4=-4x are x=-2