What is ((-3c^{-1})^4)/(-12c^7) ?

The solution to ((-3c^{-1})^4)/(-12c^7) is -(27)/(4c^{11)}

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simplify ((-3c^{-1})^4)/(-12c^7)

simplify

\frac{( - 3 c ^{- 1} ) ^{4}}{- 12 c ^{7}}

- \frac{27}{4 c ^{11}}

Solution steps

\frac{( - 3 c ^{- 1} ) ^{4}}{- 12 c ^{7}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3 c^{- 1})^{4} = (3 c^{- 1})^{4}

= \frac{( 3 c ^{- 1} ) ^{4}}{- 12 c ^{7}}

Simplify

(3 c^{- 1})^{4} : 3^{4} \cdot \frac{1}{c ^{4}}

= \frac{3 ^{4} \cdot \frac{1}{c ^{4}}}{- 12 c ^{7}}

Factor the number:

12 = 3 \cdot 4

= \frac{3 ^{4} \cdot \frac{1}{c ^{4}}}{- 3 \cdot 4 c ^{7}}

\frac{3 ^{4}}{3} = 3^{3}

= \frac{3 ^{3} \cdot \frac{1}{c ^{4}}}{- 4 c ^{7}}

Simplify

\frac{3 ^{3} \cdot \frac{1}{c ^{4}}}{- 4 c ^{7}} : - \frac{27}{c ^{11} \cdot 4}

= - \frac{27}{c ^{11} \cdot 4}

= - \frac{27}{4 c ^{11}}

3 x + 2 \geq 0

a^{2} + 4 - 4 a - 9 b^{2}

\frac{7 x + 3}{- 2} \leq 7 x + 5

- 3 x^{2} - 10 x - 8

\frac{- 9 + x}{10} = - 2

What is ((-3c^{-1})^4)/(-12c^7) ?
The solution to ((-3c^{-1})^4)/(-12c^7) is -(27)/(4c^{11)}