What are the solutions to the equation -x^2+8x+9=0 ?

The solutions to the equation -x^2+8x+9=0 are x=-1,x=9

Find the zeros of -x^2+8x+9=0

The zeros of -x^2+8x+9=0 are x=-1,x=9

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- x^{2} + 8 x + 9 = 0

x = - 1, x = 9

Solution steps

- x^{2} + 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 9 = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 ( - 1 )}, x_{2} = \frac{- 8 - 10}{2 ( - 1 )}

x = \frac{- 8 + 10}{2 ( - 1 )} : - 1

x = \frac{- 8 - 10}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

x = - 1, x = 9

x^{2} - 2 x - 3 = 0

3 x^{2} + 22 x = - 35

x^{2} - 4 x + 2 = - 2 x + 5

25 x^{2} - 60 x + 37 = 0

0.000006 x^{2} - 0.02 x + 25 = 75 - 0.02 x

What are the solutions to the equation -x^2+8x+9=0 ?
The solutions to the equation -x^2+8x+9=0 are x=-1,x=9
Find the zeros of -x^2+8x+9=0
The zeros of -x^2+8x+9=0 are x=-1,x=9