What are the solutions to the equation 9x^2+7x-4=0 ?

The solutions to the equation 9x^2+7x-4=0 are x=(-7+sqrt(193))/(18),x=(-7-sqrt(193))/(18)

Find the zeros of 9x^2+7x-4=0

The zeros of 9x^2+7x-4=0 are x=(-7+sqrt(193))/(18),x=(-7-sqrt(193))/(18)

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9 x^{2} + 7 x - 4 = 0

x = \frac{- 7 + 193}{18}, x = \frac{- 7 - 193}{18}

Decimal Notation

x = 0.38291 \dots, x = - 1.16069 \dots

Solution steps

9 x^{2} + 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

7^{2} - 4 \cdot 9 (- 4) = 193

x_{1, 2} = \frac{- 7 \pm 193}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 7 + 193}{2 \cdot 9}, x_{2} = \frac{- 7 - 193}{2 \cdot 9}

x = \frac{- 7 + 193}{2 \cdot 9} : \frac{- 7 + 193}{18}

x = \frac{- 7 - 193}{2 \cdot 9} : \frac{- 7 - 193}{18}

The solutions to the quadratic equation are:

x = \frac{- 7 + 193}{18}, x = \frac{- 7 - 193}{18}

x^{2} - 4 x - 1

x^{2} - 4 x - 5

x^{2} - 6 x + 9 = 81

81 x^{2} + 5 = 21

x, z = x^{2} e^{2 y}

What are the solutions to the equation 9x^2+7x-4=0 ?
The solutions to the equation 9x^2+7x-4=0 are x=(-7+sqrt(193))/(18),x=(-7-sqrt(193))/(18)
Find the zeros of 9x^2+7x-4=0
The zeros of 9x^2+7x-4=0 are x=(-7+sqrt(193))/(18),x=(-7-sqrt(193))/(18)