What are the solutions to the equation -8x+4x^2=-4-2x ?

The solutions to the equation -8x+4x^2=-4-2x are x= 3/4+i(sqrt(7))/4 ,x= 3/4-i(sqrt(7))/4

Find the zeros of -8x+4x^2=-4-2x

The zeros of -8x+4x^2=-4-2x are x= 3/4+i(sqrt(7))/4 ,x= 3/4-i(sqrt(7))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 8 x + 4 x^{2} = - 4 - 2 x

x = \frac{3}{4} + i \frac{7}{4}, x = \frac{3}{4} - i \frac{7}{4}

Solution steps

- 8 x + 4 x^{2} = - 4 - 2 x

Move

2 x

to the left side

4 x^{2} - 6 x = - 4

Move

4

to the left side

4 x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 4 : 27 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 4} : \frac{3}{4} + i \frac{7}{4}

x = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 4} : \frac{3}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{7}{4}, x = \frac{3}{4} - i \frac{7}{4}

r^{2} - 2 r - 15 = 0

- 2 x^{2} - 8 x - 14 = - 6

2 x^{2} - 7 x = - 6

25 x^{2} - 10 x + 4 = 0

y, x^{2} + x y + y^{2} = 1

What are the solutions to the equation -8x+4x^2=-4-2x ?
The solutions to the equation -8x+4x^2=-4-2x are x= 3/4+i(sqrt(7))/4 ,x= 3/4-i(sqrt(7))/4
Find the zeros of -8x+4x^2=-4-2x
The zeros of -8x+4x^2=-4-2x are x= 3/4+i(sqrt(7))/4 ,x= 3/4-i(sqrt(7))/4