What are the solutions to the equation -0.5x^2+40x-300=50 ?

The solutions to the equation -0.5x^2+40x-300=50 are x=10,x=70

Find the zeros of -0.5x^2+40x-300=50

The zeros of -0.5x^2+40x-300=50 are x=10,x=70

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- 0.5 x^{2} + 40 x - 300 = 50

x = 10, x = 70

Solution steps

- 0.5 x^{2} + 40 x - 300 = 50

Multiply both sides by

10

- 5 x^{2} + 400 x - 3000 = 500

Move

500

to the left side

- 5 x^{2} + 400 x - 3500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 5 ) ( - 3500 )}{2 ( - 5 )}

40 0^{2} - 4 (- 5) (- 3500) = 300

x_{1, 2} = \frac{- 400 \pm 300}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 400 + 300}{2 ( - 5 )}, x_{2} = \frac{- 400 - 300}{2 ( - 5 )}

x = \frac{- 400 + 300}{2 ( - 5 )} : 10

x = \frac{- 400 - 300}{2 ( - 5 )} : 70

The solutions to the quadratic equation are:

x = 10, x = 70

24 x^{2} + 25 (60) x - 25 (900) = 0

x^{2} + 7 x + 20 = 8

x^{2} - 14 x + 49 = 72

x^{2} + 4 x - 5 = x - 1

x^{2} - 5 x = - 3

What are the solutions to the equation -0.5x^2+40x-300=50 ?
The solutions to the equation -0.5x^2+40x-300=50 are x=10,x=70
Find the zeros of -0.5x^2+40x-300=50
The zeros of -0.5x^2+40x-300=50 are x=10,x=70