What are the solutions to the equation 2(5x-1)^2+28=30 ?

The solutions to the equation 2(5x-1)^2+28=30 are x= 2/5 ,x=0

Find the zeros of 2(5x-1)^2+28=30

The zeros of 2(5x-1)^2+28=30 are x= 2/5 ,x=0

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2 (5 x - 1)^{2} + 28 = 30

x = \frac{2}{5}, x = 0

Decimal Notation

x = 0.4, x = 0

Solution steps

2 (5 x - 1)^{2} + 28 = 30

Move

28

to the right side

2 (5 x - 1)^{2} = 2

Divide both sides by

2

(5 x - 1)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 1 = 1 : x = \frac{2}{5}

Solve

5 x - 1 = - 1 : x = 0

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = 0

2 x (1 + \frac{1}{2} x) = x (\frac{1}{2} x + 1) + 12

x^{2} - 1.3 x - 0.3 = 0

32 - 6 x^{2} = 0

c^{2} - 2 c = 6

v^{2} + 3 v - 18 = 10 v

What are the solutions to the equation 2(5x-1)^2+28=30 ?
The solutions to the equation 2(5x-1)^2+28=30 are x= 2/5 ,x=0
Find the zeros of 2(5x-1)^2+28=30
The zeros of 2(5x-1)^2+28=30 are x= 2/5 ,x=0