What are the solutions to the equation 3m^2-5m=7 ?

The solutions to the equation 3m^2-5m=7 are m=(5+sqrt(109))/6 ,m=(5-sqrt(109))/6

Find the zeros of 3m^2-5m=7

The zeros of 3m^2-5m=7 are m=(5+sqrt(109))/6 ,m=(5-sqrt(109))/6

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3 m^{2} - 5 m = 7

m = \frac{5 + 109}{6}, m = \frac{5 - 109}{6}

Decimal Notation

m = 2.57338 \dots, m = - 0.90671 \dots

Solution steps

3 m^{2} - 5 m = 7

Move

7

to the left side

3 m^{2} - 5 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 7) = 109

m_{1, 2} = \frac{- ( - 5 ) \pm 109}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 109}{2 \cdot 3}, m_{2} = \frac{- ( - 5 ) - 109}{2 \cdot 3}

m = \frac{- ( - 5 ) + 109}{2 \cdot 3} : \frac{5 + 109}{6}

m = \frac{- ( - 5 ) - 109}{2 \cdot 3} : \frac{5 - 109}{6}

The solutions to the quadratic equation are:

m = \frac{5 + 109}{6}, m = \frac{5 - 109}{6}

x, x^{2} + 4 x + 16 y^{2} - 128 y + 292 = 0

x^{2} + 8 x = 17

x^{2} - 11 x - 60 = 0

x^{2} + 7 x + 12 = 0

r^{2} - 2 = 0

What are the solutions to the equation 3m^2-5m=7 ?
The solutions to the equation 3m^2-5m=7 are m=(5+sqrt(109))/6 ,m=(5-sqrt(109))/6
Find the zeros of 3m^2-5m=7
The zeros of 3m^2-5m=7 are m=(5+sqrt(109))/6 ,m=(5-sqrt(109))/6