What are the solutions to the equation 4x^2+x-7=0 ?

The solutions to the equation 4x^2+x-7=0 are x=(-1+sqrt(113))/8 ,x=(-1-sqrt(113))/8

Find the zeros of 4x^2+x-7=0

The zeros of 4x^2+x-7=0 are x=(-1+sqrt(113))/8 ,x=(-1-sqrt(113))/8

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4 x^{2} + x - 7 = 0

x = \frac{- 1 + 113}{8}, x = \frac{- 1 - 113}{8}

Solution steps

4 x^{2} + x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 7) = 113

x_{1, 2} = \frac{- 1 \pm 113}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 113}{2 \cdot 4}, x_{2} = \frac{- 1 - 113}{2 \cdot 4}

x = \frac{- 1 + 113}{2 \cdot 4} : \frac{- 1 + 113}{8}

x = \frac{- 1 - 113}{2 \cdot 4} : \frac{- 1 - 113}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 113}{8}, x = \frac{- 1 - 113}{8}

x = \frac{9 ( - 3 ) - 2 ( - 2 )}{15 ( - 3 ) - 3 ( - 2 )}

8 - \frac{x}{3} \leq 7

(- 6)^{- 2}

x - 1 + 4 x = 3 x - 11

\frac{1 0 ^{9} + 1 0 ^{8} + 1 0 ^{7}}{555}

What are the solutions to the equation 4x^2+x-7=0 ?
The solutions to the equation 4x^2+x-7=0 are x=(-1+sqrt(113))/8 ,x=(-1-sqrt(113))/8
Find the zeros of 4x^2+x-7=0
The zeros of 4x^2+x-7=0 are x=(-1+sqrt(113))/8 ,x=(-1-sqrt(113))/8