What are the solutions to the equation solvefor q,q^2=g(-h+A) ?

The solutions to the equation solvefor q,q^2=g(-h+A) are q=sqrt(g)sqrt(-h+A),q=-sqrt(g)sqrt(-h+A)

Find the zeros of solvefor q,q^2=g(-h+A)

The zeros of solvefor q,q^2=g(-h+A) are q=sqrt(g)sqrt(-h+A),q=-sqrt(g)sqrt(-h+A)

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solve for

q, q^{2} = g (- h + A)

q = g - h + A, q = - g - h + A

Solution steps

q^{2} = g (- h + A)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = g (- h + A), q = - g (- h + A)

Simplify

g (- h + A) : g - h + A

Simplify

- g (- h + A) : - g - h + A

q = g - h + A, q = - g - h + A

27 = \frac{p ^{2}}{12}

3 x^{2} + 12 x - 13 = 0

- 12 x^{2} + 18 x + 2 = 0

2 x^{2} = x + 21

x^{2} - 1.4 x + 0.24 = 0

What are the solutions to the equation solvefor q,q^2=g(-h+A) ?
The solutions to the equation solvefor q,q^2=g(-h+A) are q=sqrt(g)sqrt(-h+A),q=-sqrt(g)sqrt(-h+A)
Find the zeros of solvefor q,q^2=g(-h+A)
The zeros of solvefor q,q^2=g(-h+A) are q=sqrt(g)sqrt(-h+A),q=-sqrt(g)sqrt(-h+A)